Problem 1
1- A
2- B
3- C
4- D
5- B
6-
Problem 2
1- A
2- C
3- A
4- B
Problem 3
1- C
2- D
3- A
4- B
Short essay questions
1. weber-fechner law:
- num. of nerve impulses in the sensory nerve fiber directly proportionate to the amplitude of the receptor potential, directly proportionate to the log intensity of the stimulus.
- wide variation in the strength of the stimuli will result in only restricted (small) variations in the amplitude of the receptor potential and frequency (impulse) of action potentials discharged along the sensory fibers.
2. Static stretch reflex:
Stimulus | Maintained weak steady passive stretch |
Receptor | Nuclear chain |
Afferent | Flower spray |
Center | Alpha motor neurons in AHC |
Efferent | Thick myelinated axons of alpha motor neurons |
Effector | Extrafusal fibers |
Response | Muscle tone (neurogenic, maintained, subtetanic muscle contraction) |
3. Declarative memory
A) short-term memory
-change the sensitivity of synaptic transmission btw neurons.
-presynaptic facilitation or inhibition at synapses
-lasts for seconds up to several minutes
-new or facilitated pathways = memory traces
B) long-term memory
-structurally changes occur in synapses such as
i. Increase num of vesicles release sites for secretion of transmitter
ii. Increase num of transmitter vesicles released
iii. Increase num of presynaptic terminals
iv. Change structure of dendrites – transmit stronger signals
4. A) photoreceptor potential
dark | light |
I. cGMP gated channels open II. Na n Ca enter outer segment III. Na accumulate in outer—go to inner segment—pump out IV. Ca also pump out V. Inward current keeps the receptor depolarized near -40mv VI. Synaptic transmitter (glutamate) is continually released. | i. Structurally change from kinked form to straight form of retinal ii. Conformational change of metarhodopsin of photopigment iii. Activation of transducin iv. Activation of PDE v. Decrease intracellular cGMP vi Closure of Na channel vii. Hyperpolarization viii. Decrease of synaptic transmission ix. Response in bipolar cells (depolarization) and other neural elements. |
B) role of cGMP
dark | light |
i. cGmp bound wif Na channel ptn—causes splints (open state) ii. Na influx iii. depolarized | I. metarhodopsin 2 activate transducin II. active transducin activate PDE—breaks cGMP into 5 GMP III. no more splinting –Na channel close up IV. decrease Na influx V. hyperpolarized |
CREDITS TO ANONYMOUS =)
2 comments:
problem 3 number 4:
answer is B
A is wrong cuz its lower thn 1khz
C is wrong cuz its 40 mili secnd
D is wrong cuz there r others which of im not shore myself, cuz there was like d cochlear, sup olivary, to the 5th n 7th.
but anyways, i think tht C is wrong.
B is right cuz d action is bilaterl to both ms in both ears
Ok, you are right. It's B.
I didn't check the answers as it was made by one of the top students. *I didn't prepare this scheme*
Thank you for pointing this out.
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