Scheme for Past year's Qs 2010

Jan 11, 2011

Problem 1
1- A
2- B
3- C
4- D
5- B
6- 

Problem 2
1- A
2- C
3- A
4- B

Problem 3
1- C
2- D
3- A
4- B

Short essay questions

1. weber-fechner law:
- num.  of nerve impulses in the sensory nerve fiber directly proportionate to the amplitude of the receptor potential, directly proportionate to the log intensity of the stimulus.
- wide variation in the strength of the stimuli will result in only restricted (small) variations in the amplitude of the receptor potential and frequency (impulse) of action potentials discharged along the sensory fibers.

2. Static stretch reflex:
Stimulus
Maintained weak steady passive stretch
Receptor
Nuclear chain
Afferent
Flower spray
Center
Alpha motor neurons in AHC
Efferent
Thick myelinated axons of alpha motor neurons
Effector
Extrafusal fibers
Response
Muscle tone (neurogenic,  maintained, subtetanic muscle contraction)

3. Declarative memory
A) short-term memory
-change the sensitivity of synaptic transmission btw neurons.
-presynaptic facilitation or inhibition at synapses
-lasts for seconds up to several minutes
-new or facilitated pathways = memory traces
B) long-term memory
-structurally changes occur in synapses such as
         i.            Increase num of  vesicles release sites for secretion of transmitter
       ii.            Increase num of transmitter vesicles released
     iii.            Increase num of presynaptic terminals
    iv.            Change structure of dendrites – transmit stronger signals

4.  A) photoreceptor potential
dark
light
       I.            cGMP gated channels open
    II.            Na n Ca enter outer segment
 III.            Na accumulate in outer—go to inner segment—pump out
 IV.            Ca also pump out
    V.            Inward current keeps the receptor depolarized near -40mv
 VI.            Synaptic transmitter (glutamate) is continually released.
                       i.  Structurally change from kinked form to straight form of retinal
                      ii. Conformational change of metarhodopsin of photopigment
                      iii.  Activation of transducin
                      iv.  Activation of PDE
                       v.    Decrease intracellular cGMP
                       vi  Closure of Na channel
                      vii. Hyperpolarization
         viii. Decrease of synaptic transmission
                        ix.    Response in bipolar cells (depolarization) and other neural elements.

B) role of cGMP
dark
light
        i.            cGmp bound wif Na channel ptn—causes splints (open state)
      ii.            Na influx
    iii.            depolarized
                      I.    metarhodopsin 2 activate transducin
                      II. active transducin activate PDE—breaks cGMP into 5 GMP
                     III.   no more splinting –Na channel close up
                      IV.    decrease Na influx
                       V.       hyperpolarized


CREDITS TO ANONYMOUS =)

2 comments:

Anonymous said...

problem 3 number 4:

answer is B

A is wrong cuz its lower thn 1khz

C is wrong cuz its 40 mili secnd

D is wrong cuz there r others which of im not shore myself, cuz there was like d cochlear, sup olivary, to the 5th n 7th.

but anyways, i think tht C is wrong.

B is right cuz d action is bilaterl to both ms in both ears

Nisaku said...

Ok, you are right. It's B.
I didn't check the answers as it was made by one of the top students. *I didn't prepare this scheme*

Thank you for pointing this out.